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6x^2-15=2
We move all terms to the left:
6x^2-15-(2)=0
We add all the numbers together, and all the variables
6x^2-17=0
a = 6; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·6·(-17)
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{102}}{2*6}=\frac{0-2\sqrt{102}}{12} =-\frac{2\sqrt{102}}{12} =-\frac{\sqrt{102}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{102}}{2*6}=\frac{0+2\sqrt{102}}{12} =\frac{2\sqrt{102}}{12} =\frac{\sqrt{102}}{6} $
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