3(x+5)+2x(x-4)=27

Solution for 3(x+5)+2x(x-4)=27 equation:

3(x+5)+2x(x-4)=27

We move all terms to the left:

3(x+5)+2x(x-4)-(27)=0

We multiply parentheses

2x^2+3x-8x+15-27=0

We add all the numbers together, and all the variables

2x^2-5x-12=0

a = 2; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·2·(-12)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*2}=\frac{-6}{4}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*2}=\frac{16}{4}
=4
$