6x2+24x-132=0

Solution for 6x2+24x-132=0 equation:

6x^2+24x-132=0

a = 6; b = 24; c = -132;
Δ = b2-4ac
Δ = 242-4·6·(-132)
Δ = 3744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3744}=\sqrt{144*26}=\sqrt{144}*\sqrt{26}=12\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{26}}{2*6}=\frac{-24-12\sqrt{26}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{26}}{2*6}=\frac{-24+12\sqrt{26}}{12}
$