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x-3=3/2x+1
We move all terms to the left:
x-3-(3/2x+1)=0
Domain of the equation: 2x+1)!=0We get rid of parentheses
x∈R
x-3/2x-1-3=0
We multiply all the terms by the denominator
x*2x-1*2x-3*2x-3=0
Wy multiply elements
2x^2-2x-6x-3=0
We add all the numbers together, and all the variables
2x^2-8x-3=0
a = 2; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·2·(-3)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{22}}{2*2}=\frac{8-2\sqrt{22}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{22}}{2*2}=\frac{8+2\sqrt{22}}{4} $
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