6x2+10x+20=2x2-18x-29

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Solution for 6x2+10x+20=2x2-18x-29 equation: 



6x^2+10x+20=2x^2-18x-29

We move all terms to the left:

6x^2+10x+20-(2x^2-18x-29)=0

We get rid of parentheses

6x^2-2x^2+10x+18x+29+20=0

We add all the numbers together, and all the variables

4x^2+28x+49=0

a = 4; b = 28; c = +49;
Δ = b2-4ac
Δ = 282-4·4·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-28}{8}=-3+1/2$

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