6x2+10x+-8=0

Solution for 6x2+10x+-8=0 equation:

6x^2+10x+-8=0

We add all the numbers together, and all the variables

6x^2+10x=0

a = 6; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·6·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*6}=\frac{-20}{12}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*6}=\frac{0}{12}
=0
$