(11x-6)+(4x+13)=202

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Solution for (11x-6)+(4x+13)=202 equation: 



(11x-6)+(4x+13)=202

We move all terms to the left:

(11x-6)+(4x+13)-(202)=0

We get rid of parentheses

11x+4x-6+13-202=0

We add all the numbers together, and all the variables

15x-195=0

We move all terms containing x to the left, all other terms to the right

15x=195

x=195/15

x=13

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