If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+102x+432=0
a = 6; b = 102; c = +432;
Δ = b2-4ac
Δ = 1022-4·6·432
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-6}{2*6}=\frac{-108}{12} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+6}{2*6}=\frac{-96}{12} =-8 $
| 2n=63/5=19 | | 5x-1=2x+47 | | y-2y=7+3 | | 4x+4+2=-26 | | -8+-4g=52 | | -3+2=9x-7 | | 2=2x+39 | | 7x-8=8x-18 | | 3x-7=x+39 | | 0.75x16=12 | | 2=2x+32 | | 3/5-2x=3x | | (4+x)/(3+x)=-2/5x | | 20x+11=-0.8x+10 | | 2x/(5-3x)=2 | | 3(2x+4)=4x+24 | | -36=2(u-4)+2u | | 9/n=n/25 | | 0.70x=2800 | | (1/x)=(5/3x)-(1/6) | | 4y=-8+16 | | 2.8h=43 | | 2x/3x+18-3x=-87 | | 24+x/6=x | | (12+x)+(12+x)=x/3 | | (12+x)+(12+x)=x | | x-28=23 | | (12+x/3)+(12+x/3)=x*3 | | (12+x/3)+(12+x/3)=x/3 | | (12+x/3)+(12+x/3)=x | | (12+x/3)*2=36 | | (12+x/3)=36 |