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(12+x/3)+(12+x/3)=x
We move all terms to the left:
(12+x/3)+(12+x/3)-(x)=0
We add all the numbers together, and all the variables
(x/3+12)+(x/3+12)-x=0
We add all the numbers together, and all the variables
-1x+(x/3+12)+(x/3+12)=0
We get rid of parentheses
-1x+x/3+x/3+12+12=0
We multiply all the terms by the denominator
-1x*3+x+x+12*3+12*3=0
We add all the numbers together, and all the variables
2x-1x*3+72=0
Wy multiply elements
2x-3x+72=0
We add all the numbers together, and all the variables
-1x+72=0
We move all terms containing x to the left, all other terms to the right
-x=-72
x=-72/-1
x=+72
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