12=(x/3x2)

Solution for 12=(x/3x2) equation:

12=(x/3x^2)

We move all terms to the left:

12-((x/3x^2))=0


Domain of the equation: 3x^2))!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-((x+12*3x^2))=0


We calculate terms in parentheses: -((x+12*3x^2)), so:

(x+12*3x^2)

We get rid of parentheses

x+12*3x^2

Wy multiply elements

36x^2+x

Back to the equation:

-(36x^2+x)


We get rid of parentheses

-36x^2-x=0

We add all the numbers together, and all the variables

-36x^2-1x=0

a = -36; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-36)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-36}=\frac{0}{-72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-36}=\frac{2}{-72}
=-1/36
$