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6x-8/2x-4=8/4
We move all terms to the left:
6x-8/2x-4-(8/4)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
6x-8/2x-4-2=0
We add all the numbers together, and all the variables
6x-8/2x-6=0
We multiply all the terms by the denominator
6x*2x-6*2x-8=0
Wy multiply elements
12x^2-12x-8=0
a = 12; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·12·(-8)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{33}}{2*12}=\frac{12-4\sqrt{33}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{33}}{2*12}=\frac{12+4\sqrt{33}}{24} $
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