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2/5x-4=x
We move all terms to the left:
2/5x-4-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+2/5x-4=0
We multiply all the terms by the denominator
-1x*5x-4*5x+2=0
Wy multiply elements
-5x^2-20x+2=0
a = -5; b = -20; c = +2;
Δ = b2-4ac
Δ = -202-4·(-5)·2
Δ = 440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{440}=\sqrt{4*110}=\sqrt{4}*\sqrt{110}=2\sqrt{110}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{110}}{2*-5}=\frac{20-2\sqrt{110}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{110}}{2*-5}=\frac{20+2\sqrt{110}}{-10} $
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