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6x-5/2x=28
We move all terms to the left:
6x-5/2x-(28)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
6x*2x-28*2x-5=0
Wy multiply elements
12x^2-56x-5=0
a = 12; b = -56; c = -5;
Δ = b2-4ac
Δ = -562-4·12·(-5)
Δ = 3376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3376}=\sqrt{16*211}=\sqrt{16}*\sqrt{211}=4\sqrt{211}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{211}}{2*12}=\frac{56-4\sqrt{211}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{211}}{2*12}=\frac{56+4\sqrt{211}}{24} $
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