(16+2x)(28+2x)=0

Solution for (16+2x)(28+2x)=0 equation:

(16+2x)(28+2x)=0

We add all the numbers together, and all the variables

(2x+16)(2x+28)=0

We multiply parentheses ..

(+4x^2+56x+32x+448)=0

We get rid of parentheses

4x^2+56x+32x+448=0

We add all the numbers together, and all the variables

4x^2+88x+448=0

a = 4; b = 88; c = +448;
Δ = b2-4ac
Δ = 882-4·4·448
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-24}{2*4}=\frac{-112}{8}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+24}{2*4}=\frac{-64}{8}
=-8
$