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6x-5-16x=7x-20x*3x
We move all terms to the left:
6x-5-16x-(7x-20x*3x)=0
We add all the numbers together, and all the variables
6x-16x-(+7x-20x*3x)-5=0
We add all the numbers together, and all the variables
-10x-(+7x-20x*3x)-5=0
We get rid of parentheses
-10x-7x+20x*3x-5=0
We add all the numbers together, and all the variables
-17x+20x*3x-5=0
Wy multiply elements
60x^2-17x-5=0
a = 60; b = -17; c = -5;
Δ = b2-4ac
Δ = -172-4·60·(-5)
Δ = 1489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{1489}}{2*60}=\frac{17-\sqrt{1489}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{1489}}{2*60}=\frac{17+\sqrt{1489}}{120} $
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