8(x-2)=5(2x+3)+3(x-4)

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Solution for 8(x-2)=5(2x+3)+3(x-4) equation: 



8(x-2)=5(2x+3)+3(x-4)

We move all terms to the left:

8(x-2)-(5(2x+3)+3(x-4))=0

We multiply parentheses

8x-(5(2x+3)+3(x-4))-16=0



We calculate terms in parentheses: -(5(2x+3)+3(x-4)), so:

5(2x+3)+3(x-4)

We multiply parentheses

10x+3x+15-12

We add all the numbers together, and all the variables

13x+3

Back to the equation:

-(13x+3)



We get rid of parentheses

8x-13x-3-16=0

We add all the numbers together, and all the variables

-5x-19=0

We move all terms containing x to the left, all other terms to the right

-5x=19

x=19/-5

x=-3+4/5

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