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6x-4x(x-9)=2(3-x)
We move all terms to the left:
6x-4x(x-9)-(2(3-x))=0
We add all the numbers together, and all the variables
6x-4x(x-9)-(2(-1x+3))=0
We multiply parentheses
-4x^2+6x+36x-(2(-1x+3))=0
We calculate terms in parentheses: -(2(-1x+3)), so:We add all the numbers together, and all the variables
2(-1x+3)
We multiply parentheses
-2x+6
Back to the equation:
-(-2x+6)
-4x^2+42x-(-2x+6)=0
We get rid of parentheses
-4x^2+42x+2x-6=0
We add all the numbers together, and all the variables
-4x^2+44x-6=0
a = -4; b = 44; c = -6;
Δ = b2-4ac
Δ = 442-4·(-4)·(-6)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{115}}{2*-4}=\frac{-44-4\sqrt{115}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{115}}{2*-4}=\frac{-44+4\sqrt{115}}{-8} $
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