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26=6+2(3+x)
We move all terms to the left:
26-(6+2(3+x))=0
We add all the numbers together, and all the variables
-(6+2(x+3))+26=0
We calculate terms in parentheses: -(6+2(x+3)), so:We get rid of parentheses
6+2(x+3)
determiningTheFunctionDomain 2(x+3)+6
We multiply parentheses
2x+6+6
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
-2x-12+26=0
We add all the numbers together, and all the variables
-2x+14=0
We move all terms containing x to the left, all other terms to the right
-2x=-14
x=-14/-2
x=+7
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