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6x-19=(12x-5-2x+7)/2
We move all terms to the left:
6x-19-((12x-5-2x+7)/2)=0
We add all the numbers together, and all the variables
6x-((10x+2)/2)-19=0
We multiply all the terms by the denominator
6x*2)-((10x+2)-19*2)=0
We add all the numbers together, and all the variables
6x*2)-((10x+2)=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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