-3x(x-4)=-2(3x+1)

Solution for -3x(x-4)=-2(3x+1) equation:

-3x(x-4)=-2(3x+1)

We move all terms to the left:

-3x(x-4)-(-2(3x+1))=0

We multiply parentheses

-3x^2+12x-(-2(3x+1))=0


We calculate terms in parentheses: -(-2(3x+1)), so:

-2(3x+1)

We multiply parentheses

-6x-2

Back to the equation:

-(-6x-2)


We get rid of parentheses

-3x^2+12x+6x+2=0

We add all the numbers together, and all the variables

-3x^2+18x+2=0

a = -3; b = 18; c = +2;
Δ = b2-4ac
Δ = 182-4·(-3)·2
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{87}}{2*-3}=\frac{-18-2\sqrt{87}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{87}}{2*-3}=\frac{-18+2\sqrt{87}}{-6}
$