6x-18=3(2x-3)-(2x+6)

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Solution for 6x-18=3(2x-3)-(2x+6) equation: 



6x-18=3(2x-3)-(2x+6)

We move all terms to the left:

6x-18-(3(2x-3)-(2x+6))=0



We calculate terms in parentheses: -(3(2x-3)-(2x+6)), so:

3(2x-3)-(2x+6)

We multiply parentheses

6x-(2x+6)-9

We get rid of parentheses

6x-2x-6-9

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We get rid of parentheses

6x-4x+15-18=0

We add all the numbers together, and all the variables

2x-3=0

We move all terms containing x to the left, all other terms to the right

2x=3

x=3/2

x=1+1/2

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