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6x-16=2/3(3x+12
We move all terms to the left:
6x-16-(2/3(3x+12)=0
Domain of the equation: 3(3x+12)-16!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3(3x+12)!=16
x∈R
6x*3(3x+12)-16-(2=0
We add all the numbers together, and all the variables
6x*3(3x+12)=0
Wy multiply elements
18x^2(3=0
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