If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1)/(2)-(1)/(8)q=(q-1)/(4)
We move all terms to the left:
(1)/(2)-(1)/(8)q-((q-1)/(4))=0
Domain of the equation: 8q!=0We calculate fractions
q!=0/8
q!=0
q∈R
(-((q-1)*8q*2)/64q^2+128q^2/64q^2+()/64q^2=0
We can not solve this equation
| 10=8+p/10 | | 10(g+4)=70 | | r-80/3=6 | | 24/20=x/50 | | 10=8+p10 | | t-35/9=5 | | 7(2x—1)—11=6+6x | | 5=t-35/9 | | 3r-9=-30 | | b/2-3=7 | | -4-9(x-6)=-3(3x+5) | | −3(2x+7)=18 | | x-9/8=x+3/2 | | -7(n+7)=-119 | | 30*10*3x=90 | | 26x+6+7x+2=20 | | 16x2+64x+65=0 | | 29=15-x | | z^2-2z-4=0 | | 3.14x49=153.86 | | x=-3x^2–2x+4 | | 6*6*6*6*6*6=6x | | -8p=3-1/4 | | 26c=338 | | 82=-5v-8 | | 15+5x=5x-7 | | -8p=-3,1/4 | | e/3=-5 | | 8k-4k=-12 | | 1/4=a+3/8 | | 6x-56+3x-17=90 | | 100=32x-12(x+5) |