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6x-14=7/3x
We move all terms to the left:
6x-14-(7/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6x-(+7/3x)-14=0
We get rid of parentheses
6x-7/3x-14=0
We multiply all the terms by the denominator
6x*3x-14*3x-7=0
Wy multiply elements
18x^2-42x-7=0
a = 18; b = -42; c = -7;
Δ = b2-4ac
Δ = -422-4·18·(-7)
Δ = 2268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2268}=\sqrt{324*7}=\sqrt{324}*\sqrt{7}=18\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-18\sqrt{7}}{2*18}=\frac{42-18\sqrt{7}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+18\sqrt{7}}{2*18}=\frac{42+18\sqrt{7}}{36} $
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