If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3(2x+10/5=2x-5
We move all terms to the left:
3(2x+10/5-(2x-5)=0
Domain of the equation: 5-(2x-5)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(2x-5)!=-5
x∈R
3(2x+10=0
| 2(x+5)/3=6 | | (X+1)(x+2)=10 | | 24=-6/7w | | (5t-3)^1/9-(2t-4)1/9=0 | | 55/44=22/x | | 1.2=10-x-10x÷100 | | 2.17=7x-13 | | 95/38=57/x | | 7x-13=6x-7 | | X/4-2x-1/3=x-5/6 | | 1=-5x-3 | | 2x+3(0)=15 | | 2|6-5/3x|+8=26 | | x=40-10 | | x=10-40 | | 1=-x-7 | | 3(2x+3)=6(x+3) | | -x-7=-5x-3 | | 2(n+5)=3(20+4n) | | -3(6n-6)+2n=24 | | -1=-7x+9 | | -7x+9=7x+23 | | 2|2x-7|+4=10 | | -1=11x+1 | | 11x+1=3x-7 | | 5x+1+4x=19 | | 5/5x^2+32x+12-1/8=1/x^2-36 | | 2+4x+2x=118 | | 4(1+2x)+5=5(x+6) | | c^2+8c+2=0 | | 2x-9-x=0 | | 2(4m-9)-3(m+5)=0 |