6x-10=x(2x-3)

Solution for 6x-10=x(2x-3) equation:

6x-10=x(2x-3)

We move all terms to the left:

6x-10-(x(2x-3))=0


We calculate terms in parentheses: -(x(2x-3)), so:

x(2x-3)

We multiply parentheses

2x^2-3x

Back to the equation:

-(2x^2-3x)


We get rid of parentheses

-2x^2+6x+3x-10=0

We add all the numbers together, and all the variables

-2x^2+9x-10=0

a = -2; b = 9; c = -10;
Δ = b2-4ac
Δ = 92-4·(-2)·(-10)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*-2}=\frac{-10}{-4}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*-2}=\frac{-8}{-4}
=+2
$