3x+6+15=16+(3x-4)+20

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Solution for 3x+6+15=16+(3x-4)+20 equation: 



3x+6+15=16+(3x-4)+20

We move all terms to the left:

3x+6+15-(16+(3x-4)+20)=0

We add all the numbers together, and all the variables

3x-(16+(3x-4)+20)+21=0



We calculate terms in parentheses: -(16+(3x-4)+20), so:

16+(3x-4)+20

determiningTheFunctionDomain
(3x-4)+16+20

We add all the numbers together, and all the variables

(3x-4)+36

We get rid of parentheses

3x-4+36

We add all the numbers together, and all the variables

3x+32

Back to the equation:

-(3x+32)



We get rid of parentheses

3x-3x-32+21=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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