6x-10=2(x+1)-3(3+4)

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Solution for 6x-10=2(x+1)-3(3+4) equation: 



6x-10=2(x+1)-3(3+4)

We move all terms to the left:

6x-10-(2(x+1)-3(3+4))=0

We add all the numbers together, and all the variables

6x-(2(x+1)-37)-10=0



We calculate terms in parentheses: -(2(x+1)-37), so:

2(x+1)-37

We multiply parentheses

2x+2-37

We add all the numbers together, and all the variables

2x-35

Back to the equation:

-(2x-35)



We get rid of parentheses

6x-2x+35-10=0

We add all the numbers together, and all the variables

4x+25=0

We move all terms containing x to the left, all other terms to the right

4x=-25

x=-25/4

x=-6+1/4

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