6x-10=(3x+3)+(2x+1)

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Solution for 6x-10=(3x+3)+(2x+1) equation: 



6x-10=(3x+3)+(2x+1)

We move all terms to the left:

6x-10-((3x+3)+(2x+1))=0



We calculate terms in parentheses: -((3x+3)+(2x+1)), so:

(3x+3)+(2x+1)

We get rid of parentheses

3x+2x+3+1

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

6x-5x-4-10=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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