5(c-3)+2c=41

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Solution for 5(c-3)+2c=41 equation: 



5(c-3)+2c=41

We move all terms to the left:

5(c-3)+2c-(41)=0

We add all the numbers together, and all the variables

2c+5(c-3)-41=0

We multiply parentheses

2c+5c-15-41=0

We add all the numbers together, and all the variables

7c-56=0

We move all terms containing c to the left, all other terms to the right

7c=56

c=56/7

c=8

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