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6x-1(2x+1)+2=5x-(2x+1)
We move all terms to the left:
6x-1(2x+1)+2-(5x-(2x+1))=0
We calculate terms in parentheses: -(5x-(2x+1)), so:We get rid of parentheses
5x-(2x+1)
We get rid of parentheses
5x-2x-1
We add all the numbers together, and all the variables
3x-1
Back to the equation:
-(3x-1)
6x-1(2x+1)-3x+1+2=0
We add all the numbers together, and all the variables
3x-1(2x+1)+3=0
We move all terms containing x to the left, all other terms to the right
3x-1(2x+1)=-3
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