(3y+99)+(12y+9)=270

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Solution for (3y+99)+(12y+9)=270 equation: 



(3y+99)+(12y+9)=270

We move all terms to the left:

(3y+99)+(12y+9)-(270)=0

We get rid of parentheses

3y+12y+99+9-270=0

We add all the numbers together, and all the variables

15y-162=0

We move all terms containing y to the left, all other terms to the right

15y=162

y=162/15

y=10+4/5

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