6x-(14-(x-4))=7x-2x-19-(3x+2))

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Solution for 6x-(14-(x-4))=7x-2x-19-(3x+2)) equation:



6x-(14-(x-4))=7x-2x-19-(3x+2))
We move all terms to the left:
6x-(14-(x-4))-(7x-2x-19-(3x+2)))=0
We calculate terms in parentheses: -(14-(x-4)), so:
14-(x-4)
determiningTheFunctionDomain -(x-4)+14
We get rid of parentheses
-x+4+14
We add all the numbers together, and all the variables
-1x+18
Back to the equation:
-(-1x+18)
We calculate terms in parentheses: -(7x-2x-19-(3x+2))), so:
7x-2x-19-(3x+2))
determiningTheFunctionDomain 7x-2x-(3x+2))-19
We add all the numbers together, and all the variables
5x-(3x+2))-19
Back to the equation:
-(5x-(3x+2))-19)
We add all the numbers together, and all the variables
6x-(-1x+18)-(5x-(3x+2))=0
We get rid of parentheses
6x+1x-(5x-(3x+2))-18=0
We calculate terms in parentheses: -(5x-(3x+2)), so:
5x-(3x+2)
We get rid of parentheses
5x-3x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We add all the numbers together, and all the variables
7x-(2x-2)-18=0
We get rid of parentheses
7x-2x+2-18=0
We add all the numbers together, and all the variables
5x-16=0
We move all terms containing x to the left, all other terms to the right
5x=16
x=16/5
x=3+1/5

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