(7m-3)/2=(6m+1)/3+1

Solution for (7m-3)/2=(6m+1)/3+1 equation:

(7m-3)/2=(6m+1)/3+1

We move all terms to the left:

(7m-3)/2-((6m+1)/3+1)=0

We calculate fractions


(21m-9)/()+(-((6m+1)*2)/()=0


We calculate terms in parentheses: +(-((6m+1)*2)/(), so:

-((6m+1)*2)/(

We multiply all the terms by the denominator


-((6m+1)*2)


We calculate terms in parentheses: -((6m+1)*2), so:

(6m+1)*2

We multiply parentheses

12m+2

Back to the equation:

-(12m+2)


We get rid of parentheses

-12m-2

Back to the equation:

+(-12m-2)


We get rid of parentheses

(21m-9)/()-12m-2=0

We multiply all the terms by the denominator


(21m-9)-12m*()-2*()=0

We add all the numbers together, and all the variables

(21m-9)-12m*()=0

We get rid of parentheses

21m-12m*()-9=0

We move all terms containing m to the left, all other terms to the right

21m-12m*()=9