6x+7+4x-3=4x-12-2x+8

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Solution for 6x+7+4x-3=4x-12-2x+8 equation: 



6x+7+4x-3=4x-12-2x+8

We move all terms to the left:

6x+7+4x-3-(4x-12-2x+8)=0

We add all the numbers together, and all the variables

6x+4x-(2x-4)+7-3=0

We add all the numbers together, and all the variables

10x-(2x-4)+4=0

We get rid of parentheses

10x-2x+4+4=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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