3(m+2)-(2m-8)=16

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Solution for 3(m+2)-(2m-8)=16 equation: 



3(m+2)-(2m-8)=16

We move all terms to the left:

3(m+2)-(2m-8)-(16)=0

We multiply parentheses

3m-(2m-8)+6-16=0

We get rid of parentheses

3m-2m+8+6-16=0

We add all the numbers together, and all the variables

m-2=0

We move all terms containing m to the left, all other terms to the right

m=2

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