6x+4(4-x)=48

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Solution for 6x+4(4-x)=48 equation: 



6x+4(4-x)=48

We move all terms to the left:

6x+4(4-x)-(48)=0

We add all the numbers together, and all the variables

6x+4(-1x+4)-48=0

We multiply parentheses

6x-4x+16-48=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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