6x+38=2(x+1)

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Solution for 6x+38=2(x+1) equation: 



6x+38=2(x+1)

We move all terms to the left:

6x+38-(2(x+1))=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

6x-2x-2+38=0

We add all the numbers together, and all the variables

4x+36=0

We move all terms containing x to the left, all other terms to the right

4x=-36

x=-36/4

x=-9

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