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1/2(t+3)-2t=5
We move all terms to the left:
1/2(t+3)-2t-(5)=0
Domain of the equation: 2(t+3)!=0We add all the numbers together, and all the variables
t∈R
-2t+1/2(t+3)-5=0
We multiply all the terms by the denominator
-2t*2(t+3)-5*2(t+3)+1=0
Wy multiply elements
-4t^2(t-10t(t+1=0
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