6x+24=2x(x+4)

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Solution for 6x+24=2x(x+4) equation:



6x+24=2x(x+4)
We move all terms to the left:
6x+24-(2x(x+4))=0
We calculate terms in parentheses: -(2x(x+4)), so:
2x(x+4)
We multiply parentheses
2x^2+8x
Back to the equation:
-(2x^2+8x)
We get rid of parentheses
-2x^2+6x-8x+24=0
We add all the numbers together, and all the variables
-2x^2-2x+24=0
a = -2; b = -2; c = +24;
Δ = b2-4ac
Δ = -22-4·(-2)·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*-2}=\frac{-12}{-4} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*-2}=\frac{16}{-4} =-4 $

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