-10(y+3)+5(3y-6)=4(y-6)+13

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Solution for -10(y+3)+5(3y-6)=4(y-6)+13 equation: 



-10(y+3)+5(3y-6)=4(y-6)+13

We move all terms to the left:

-10(y+3)+5(3y-6)-(4(y-6)+13)=0

We multiply parentheses

-10y+15y-(4(y-6)+13)-30-30=0



We calculate terms in parentheses: -(4(y-6)+13), so:

4(y-6)+13

We multiply parentheses

4y-24+13

We add all the numbers together, and all the variables

4y-11

Back to the equation:

-(4y-11)



We add all the numbers together, and all the variables

5y-(4y-11)-60=0

We get rid of parentheses

5y-4y+11-60=0

We add all the numbers together, and all the variables

y-49=0

We move all terms containing y to the left, all other terms to the right

y=49

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