6x+2-3x+4=4(x+2)+4x-2

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Solution for 6x+2-3x+4=4(x+2)+4x-2 equation: 



6x+2-3x+4=4(x+2)+4x-2

We move all terms to the left:

6x+2-3x+4-(4(x+2)+4x-2)=0

We add all the numbers together, and all the variables

3x-(4(x+2)+4x-2)+6=0



We calculate terms in parentheses: -(4(x+2)+4x-2), so:

4(x+2)+4x-2

We add all the numbers together, and all the variables

4x+4(x+2)-2

We multiply parentheses

4x+4x+8-2

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We get rid of parentheses

3x-8x-6+6=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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