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-2/5z+3=1/5z+11
We move all terms to the left:
-2/5z+3-(1/5z+11)=0
Domain of the equation: 5z!=0
z!=0/5
z!=0
z∈R
Domain of the equation: 5z+11)!=0We get rid of parentheses
z∈R
-2/5z-1/5z-11+3=0
We multiply all the terms by the denominator
-11*5z+3*5z-2-1=0
We add all the numbers together, and all the variables
-11*5z+3*5z-3=0
Wy multiply elements
-55z+15z-3=0
We add all the numbers together, and all the variables
-40z-3=0
We move all terms containing z to the left, all other terms to the right
-40z=3
z=3/-40
z=-3/40
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