6x+2-(4x-3)-10=-9(x-5)+5x-8

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Solution for 6x+2-(4x-3)-10=-9(x-5)+5x-8 equation: 



6x+2-(4x-3)-10=-9(x-5)+5x-8

We move all terms to the left:

6x+2-(4x-3)-10-(-9(x-5)+5x-8)=0

We add all the numbers together, and all the variables

6x-(4x-3)-(-9(x-5)+5x-8)-8=0

We get rid of parentheses

6x-4x-(-9(x-5)+5x-8)+3-8=0



We calculate terms in parentheses: -(-9(x-5)+5x-8), so:

-9(x-5)+5x-8

We add all the numbers together, and all the variables

5x-9(x-5)-8

We multiply parentheses

5x-9x+45-8

We add all the numbers together, and all the variables

-4x+37

Back to the equation:

-(-4x+37)



We add all the numbers together, and all the variables

2x-(-4x+37)-5=0

We get rid of parentheses

2x+4x-37-5=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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