-5(2v-3)=1-6(2v+1)

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Solution for -5(2v-3)=1-6(2v+1) equation:



-5(2v-3)=1-6(2v+1)
We move all terms to the left:
-5(2v-3)-(1-6(2v+1))=0
We multiply parentheses
-10v-(1-6(2v+1))+15=0
We calculate terms in parentheses: -(1-6(2v+1)), so:
1-6(2v+1)
determiningTheFunctionDomain -6(2v+1)+1
We multiply parentheses
-12v-6+1
We add all the numbers together, and all the variables
-12v-5
Back to the equation:
-(-12v-5)
We get rid of parentheses
-10v+12v+5+15=0
We add all the numbers together, and all the variables
2v+20=0
We move all terms containing v to the left, all other terms to the right
2v=-20
v=-20/2
v=-10

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