6x+2(4x-3)=6+5(x+3)

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Solution for 6x+2(4x-3)=6+5(x+3) equation: 



6x+2(4x-3)=6+5(x+3)

We move all terms to the left:

6x+2(4x-3)-(6+5(x+3))=0

We multiply parentheses

6x+8x-(6+5(x+3))-6=0



We calculate terms in parentheses: -(6+5(x+3)), so:

6+5(x+3)

determiningTheFunctionDomain
5(x+3)+6

We multiply parentheses

5x+15+6

We add all the numbers together, and all the variables

5x+21

Back to the equation:

-(5x+21)



We add all the numbers together, and all the variables

14x-(5x+21)-6=0

We get rid of parentheses

14x-5x-21-6=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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