-3x-4(4x-8)x=3(-8x-1)x=7

Solution for -3x-4(4x-8)x=3(-8x-1)x=7 equation:

-3x-4(4x-8)x=3(-8x-1)x=7

We move all terms to the left:

-3x-4(4x-8)x-(3(-8x-1)x)=0

We multiply parentheses

-16x^2-3x+32x-(3(-8x-1)x)=0


We calculate terms in parentheses: -(3(-8x-1)x), so:

3(-8x-1)x

We multiply parentheses

-24x^2-3x

Back to the equation:

-(-24x^2-3x)


We add all the numbers together, and all the variables

-16x^2-(-24x^2-3x)+29x=0

We get rid of parentheses

-16x^2+24x^2+3x+29x=0

We add all the numbers together, and all the variables

8x^2+32x=0

a = 8; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·8·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*8}=\frac{-64}{16}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*8}=\frac{0}{16}
=0
$