6x+1=2(3x+2)-3

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Solution for 6x+1=2(3x+2)-3 equation: 



6x+1=2(3x+2)-3

We move all terms to the left:

6x+1-(2(3x+2)-3)=0



We calculate terms in parentheses: -(2(3x+2)-3), so:

2(3x+2)-3

We multiply parentheses

6x+4-3

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We get rid of parentheses

6x-6x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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