(m+5)(m-6)=-24

Solution for (m+5)(m-6)=-24 equation:

(m+5)(m-6)=-24

We move all terms to the left:

(m+5)(m-6)-(-24)=0

We add all the numbers together, and all the variables

(m+5)(m-6)+24=0

We multiply parentheses ..

(+m^2-6m+5m-30)+24=0

We get rid of parentheses

m^2-6m+5m-30+24=0

We add all the numbers together, and all the variables

m^2-1m-6=0

a = 1; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·1·(-6)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2*1}=\frac{-4}{2}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2*1}=\frac{6}{2}
=3
$