6x+(3x-7)=x-(4x-1)

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Solution for 6x+(3x-7)=x-(4x-1) equation: 



6x+(3x-7)=x-(4x-1)

We move all terms to the left:

6x+(3x-7)-(x-(4x-1))=0

We get rid of parentheses

6x+3x-(x-(4x-1))-7=0



We calculate terms in parentheses: -(x-(4x-1)), so:

x-(4x-1)

We get rid of parentheses

x-4x+1

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

9x-(-3x+1)-7=0

We get rid of parentheses

9x+3x-1-7=0

We add all the numbers together, and all the variables

12x-8=0

We move all terms containing x to the left, all other terms to the right

12x=8

x=8/12

x=2/3

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